Compare the Triplets - HackerRank Coding Challenge

 Problem description: 

Alice and Bob each created one problem for HackerRank. A reviewer rates the two challenges, awarding points on a scale from 1 to 100 for three categories: problem clarity, originality, and difficulty.

The rating for Alice's challenge is the triplet a = (a[0], a[1], a[2]), and the rating for Bob's challenge is the triplet b = (b[0], b[1], b[2]).

The task is to find their comparison points by comparing a[0] with b[0], a[1] with b[1], and a[2] with b[2].

• If a[i] > b[i], then Alice is awarded 1 point.
• If a[i] < b[i], then Bob is awarded 1 point.
• If a[i] = b[i], then neither person receives a point.

Comparison points is the total points a person earned.

Given a and b, determine their respective comparison points.

Example

a = [1, 2, 3]
b = [3, 2, 1]

• For elements *0*, Bob is awarded a point because a[0] .
• For the equal elements a[1] and b[1], no points are earned.
• Finally, for elements 2, a[2] > b[2] so Alice receives a point.

The return array is [1, 1] with Alice's score first and Bob's second.

Function Description

Complete the function compareTriplets in the editor below.

compareTriplets has the following parameter(s):

• int a[3]: Alice's challenge rating
• int b[3]: Bob's challenge rating

Return

• int[2]: Alice's score is in the first position, and Bob's score is in the second.

Input Format

The first line contains 3 space-separated integers, a[0], a[1], and a[2], the respective values in triplet a.
The second line contains 3 space-separated integers, b[0], b[1], and b[2], the respective values in triplet b.

Constraints

• 1 ≤ a[i] ≤ 100
• 1 ≤ b[i] ≤ 100

Sample Input 0

5 6 7
3 6 10

Sample Output 0

1 1

Sample Input 1

17 28 30
99 16 8
Sample Output 1
2 1

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Solution in cpp:

vector<int> compareTriplets(vector<int> a, vector<int> b) {
    int aC=0, bC=0;
    for(int i=0; i<a.size(); i++){
        if(a[i]>b[i]){
            aC++;
        }
        else if(a[i]<b[i]){
            bC++;
        }
        else if(a[i]==b[i]){
            continue;
        }
    }
    vector<int>ans;
    ans.push_back(aC);
    ans.push_back(bC);
    
    return ans;
}